Compute the inverse hyperbolic cotangent of x


  1. Calculate the inverse hyperbolic cotangent of a number:

    julia> x = 1.5;
    julia> acoth(x)

    This example calculates the inverse hyperbolic cotangent of the number x.

  2. Handle negative input:

    julia> y = -0.8;
    julia> acoth(y)

    It correctly handles negative input and returns the inverse hyperbolic cotangent.

  3. Use acoth in an expression:
    julia> z = acoth(2.7) + acoth(1.3);
    julia> z

    It can be used within a larger expression to perform calculations involving inverse hyperbolic cotangents.

Common mistake example:

julia> acoth("hello")
ERROR: MethodError: no method matching acoth(::String)

In this example, the input provided is of type String which is not a valid argument for the acoth function. Make sure to provide a numeric value as an argument to acoth.

See Also

acos, acosd, acosh, acot, acotd, acoth, acsc, acscd, acsch, asec, asecd, asech, asin, asind, asinh, atan, atan2, atand, atanh, cos, cosc, cosd, cosh, cospi, cot, cotd, coth, csc, cscd, csch, deg2rad, rad2deg, sin, sinc, sind, sinh, sinpi, tan, tand, tanh,

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